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Old 01-14-2012, 10:59 PM   #856
Scooby Newbie
Member#: 280483
Join Date: Apr 2011
Chapter/Region: MWSOC
Location: Milwaukee,Wi
03 Bugeye WRX


Originally Posted by JSarv View Post
Lets do a reference:
30psiA (15.3psiG @ sea level)
@ 30psiA and 3000 rpms SD Load Compensation is a conservative 5%.

30*(0.0764448)+(-0.00683594)*1.05= 2.40 G/Rev

So @ 3000 rpms and 30psiA (15.3psi relative) you will have a load value of 2.40 G/Rev. This is theoretical...
im just starting out learning SD. so i hope im not just being a noob. but your equation doesn't equal 2.40
idk if you just rounded up or if the math needs to be exact.

but i come up with 2.28616626

just wondering how/why you used 2.40 as the g/rev when it isnt what the math comes out too.

again just trying to learn. thanks.

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